fr+solution+1

· (2, 1);{//y//<-//x//+4 {//y//≤//x//+1 · ( 2, 1 ) substitute the 2 and 1 for x and y in both inequalities! //__y__//__<-//X//+4__ 1 <- 2 +4  1<2  TRUE 1 ≤ 2 +1 1 ≤3 TRUE (2, 1) solution